Codeforces Beta Round 22 (Div. 2 Only)

5 problems from Codeforces Beta Round 22 (Div. 2 Only) (contest 22), difficulty 800-2300. 4/5 solutions verified against sample I/O.

5 items

Codeforces Beta Round 22 (Div. 2 Only)

Div. 2 | 5 problems | 4/5 verified | Difficulty 800-2300 | 7m 39s

# Problem Rating Tags Accepted Time ✓
A Second Order Statistics 800 brute-force 27,079 1m 21s ✓
B Bargaining Table 1500 brute-force, dp 4,782 1m 40s ✓
C System Administrator 1700 graphs 3,806 1m 25s
D Segments 1900 greedy, sortings 3,411 1m 25s ✓
E Scheme 2300 dfs-and-similar, graphs, trees 2,078 1m 48s ✓
Practice › Codeforces Solutions › Codeforces Beta Round 22 (Div. 2 Only) ›

CF 22A - Second Order Statistics

We are given a small array of integers and need to find the smallest value that is strictly larger than the minimum element in the array.
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Practice › Codeforces Solutions › Codeforces Beta Round 22 (Div. 2 Only) ›

CF 22B - Bargaining Table

The office floor is represented as an n × m grid. Each cell is either free, written as 0, or blocked by furniture, written as 1. We want to place one rectangular table whose sides stay aligned with the grid. Every cell covered by the rectangle must be free.
codeforces competitive-programming brute-force dp May 28, 2026
Practice › Codeforces Solutions › Codeforces Beta Round 22 (Div. 2 Only) ›

CF 22C - System Administrator

We are asked to design a network of servers where each server is a node, and each connection between two servers is an undirected edge. There are n servers and we are allowed exactly m connections.
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Practice › Codeforces Solutions › Codeforces Beta Round 22 (Div. 2 Only) ›

CF 22D - Segments

We are given several closed intervals on the number line. A nail placed at an integer coordinate covers every segment that contains that coordinate, including endpoints.
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Practice › Codeforces Solutions › Codeforces Beta Round 22 (Div. 2 Only) ›

CF 22E - Scheme

Each person points to exactly one other person. If someone learns the news, they call the person they point to, who then calls the next person, and so on. We may add extra directed edges of the form x -> y, meaning person x must also call y.
codeforces competitive-programming dfs-and-similar graphs trees May 28, 2026