CF 1539E - Game with Cards

Represent each integer in base $b$ as a doubly linked list of digits $$(v{n-1}, v{n-2}, dots, v0),$$ where each node contains one digit $vi in {0, dots, b-1}$, together with pointers $$text{left}(i), text{right}(i)$$ to adjacent digits.

CF 1539E - Game with Cards

Rating: 2500
Tags: binary search, constructive algorithms, data structures, dp, greedy, implementation
Solve time: 2m 5s
Verified: no

Solution

Representation of integers

Represent each integer in base $b$ as a doubly linked list of digits

$$(v_{n-1}, v_{n-2}, \dots, v_0),$$

where each node contains one digit $v_i \in {0, \dots, b-1}$, together with pointers

$$\text{left}(i), \text{right}(i)$$

to adjacent digits. The head pointer refers to the most significant digit, the tail pointer to the least significant digit.

Each integer record also stores a sign bit.

Memory allocation uses a free-list of unused nodes. Allocation and deallocation are constant-time operations by taking or returning nodes to the free-list.

Addition subroutine

To compute $x + y$:

  1. Align the least significant digits of $x$ and $y$.
  2. Traverse both lists from least significant to most significant digit.
  3. Maintain a carry $c \in {0,1}$.
  4. For each position, compute

$$s_i = x_i + y_i + c, \quad z_i = s_i \bmod b, \quad c = \lfloor s_i / b \rfloor.$$ 5. Allocate a new node for each digit $z_i$ and link it into the result list. 6. If a carry remains at the end, allocate a new most significant node.

This runs in time proportional to the maximum length of the inputs.

Subtraction subroutine

To compute $x - y$, assume first that $|x| \ge |y|$.

  1. Traverse from least significant digit.
  2. Maintain borrow $c \in {0,1}$.
  3. Compute

$$d_i = x_i - y_i - c.$$ 4. If $d_i < 0$, set $d_i \leftarrow d_i + b$ and $c \leftarrow 1$, otherwise $c \leftarrow 0$. 5. Store each $d_i$ in a newly allocated node. 6. Remove leading zeros at the end by returning nodes to the free-list.

If $|x| < |y|$, compute $y - x$ and attach a minus sign.

Multiplication subroutine

To compute $x \cdot y$:

  1. Initialize result as zero.
  2. For each digit $y_j$, proceed from least significant to most significant:
  • Multiply $x$ by digit $y_j$, producing a partial product.
  • Shift the partial product by $j$ positions (implemented by offset in list structure).
  • Add the shifted partial product to the accumulated result using the addition subroutine.
  1. Each partial product digit is computed with carries exactly as in school multiplication.

Each intermediate node is allocated dynamically; no preallocation is required.

Division subroutine

To compute $x / y$, assume $y \ne 0$:

  1. Normalize by ensuring the leading digit of $y$ is nonzero.
  2. Perform long division from most significant digit of $x$.
  3. Maintain a current remainder $r$, initially zero.
  4. At each step, extend $r$ by one digit from $x$.
  5. Determine the largest digit $q_i \in {0, \dots, b-1}$ such that

$$q_i y \le r.$$ 6. Subtract $q_i y$ from $r$ using the subtraction subroutine. 7. Append $q_i$ to the quotient list.

All comparisons and multiplications are performed using the previously defined routines.

Memory management correctness

All results are constructed using newly allocated nodes from the free-list. When digits are removed (for example leading zeros), nodes are returned to the free-list immediately. No search for free memory is required.

Thus the algorithm uses linked allocation efficiently and respects the constraint that memory is used only as available.

Conclusion

The four subroutines for addition, subtraction, multiplication, and division operate correctly on arbitrary-length integers represented as linked digit lists, using only local digit operations, carry/borrow propagation, and dynamic memory allocation.

This satisfies the requirement of implementing arbitrary-precision integer arithmetic using linked memory allocation.