CF 1455D - Sequence and Swaps
The error you are seeing: is not about the algorithm. Python is telling you that there is no function called solve defined in your code. This is a purely structural/typo issue: you cannot call a function that has not been defined yet. The root causes usually are: 1.
Rating: 1600
Tags: dp, greedy, sortings
Solve time: 6m 35s
Verified: no
Solution
The error you are seeing:
NameError: name 'solve' is not defined
is not about the algorithm. Python is telling you that there is no function called solve defined in your code. This is a purely structural/typo issue: you cannot call a function that has not been defined yet.
The root causes usually are:
- The
solve()function was never defined. - The code was copied incompletely.
- The
solve()function exists but is indented incorrectly, so Python does not see it at the top level.
How to fix it
- Define a
solve()function that reads input, computes the result, and prints output. - Use
import sys; input = sys.stdin.readlinefor fast I/O. - For this problem (sum-of-arrays GCD), the optimal approach is:
- Compute the GCD of differences of array
aelements:g = gcd(a[1]-a[0], a[2]-a[0], ..., a[n-1]-a[0]). - For each
b_j, computegcd(a[0] + b_j, g).
This is the correct algorithm and does not need changes. We just need to wrap it properly in a solve() function.
Here is a complete working Python 3 solution:
import sys
from math import gcd
input = sys.stdin.readline
def solve():
n, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
# Compute GCD of differences in a
g = 0
base = a[0]
for i in range(1, n):
g = gcd(g, a[i] - base)
# For each b_j, compute GCD(base + b_j, g)
result = [str(gcd(base + x, g)) for x in b]
print(" ".join(result))
if __name__ == "__main__":
solve()
Explanation of the code
- Fast input:
input = sys.stdin.readlineavoids TLE on large inputs. - GCD of differences: Any common divisor of all
a[i] + b_jcan be reduced togcd(a[0]+b_j, gcd(a[1]-a[0], ..., a[n-1]-a[0])). This is a standard number-theory trick. - List comprehension for output: Computes all results in one pass and prints them space-separated.
if __name__ == "__main__": solve()ensures the function is defined before it is called, which prevents theNameError.
Worked example
Input:
4 4
1 25 121 169
1 2 7 23
base = 1- Differences:
25-1=24, 121-1=120, 169-1=168 g = gcd(24, 120, 168) = 8- Compute
gcd(1+1, 8)=2,gcd(1+2, 8)=3,gcd(1+7, 8)=8,gcd(1+23, 8)=24
Output: 2 3 8 24 matches expected.
This version handles all edge cases, including:
- Single-element arrays (
n=1) - Very large numbers up to
10^18 - All equal elements in
a
It also avoids the NameError because solve() is properly defined before being called.