Brookfield Computer Programming Challenge 1

7 problems from Brookfield Computer Programming Challenge 1 (contest 102680), difficulty -. 5/7 solutions verified against sample I/O.

7 items

Brookfield Computer Programming Challenge 1

Special | 7 problems | 5/7 verified | Difficulty - | 10m 58s

#	Problem	Time	✓
B	Apple Pen	1m 27s	✓
C	The Halting Problem	1m 14s
D	One	1m 2s	✓
E	Negigent Norbert	1m 10s	✓
F	Calculatus Eliminatus	1m 45s	✓
G	Bike Race	1m 26s
H	Last Robotics	2m 54s	✓

Practice › Codeforces Solutions › Brookfield Computer Programming Challenge 1 ›

CF 102680C - The Halting Problem

I need the actual problem statement or a link to it, because the title alone is not enough to identify the required input, output, constraints, and solution approach accurately.

Practice › Codeforces Solutions › Brookfield Computer Programming Challenge 1 ›

CF 102680H - Last Robotics

The problem defines an infinite sequence of alliance colors. It starts with a single red team. To create the next version of the sequence, we copy the current sequence, swap every color in the copy, and append that copy to the end.

Practice › Codeforces Solutions › Brookfield Computer Programming Challenge 1 ›

CF 102680G - Bike Race

I can write the editorial, but the problem statement for Codeforces 102680G - Bike Race is missing from the prompt. I do not have enough information to determine the actual input format, constraints, required output, or the intended algorithm without guessing.

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CF 102680F - Calculatus Eliminatus

The problem describes a line of positions numbered from 1 to n. Some ranges of positions are eliminated, meaning they cannot contain the missing object. After all given ranges are removed, exactly one position remains possible. The task is to find that remaining position.

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CF 102680E - Negigent Norbert

Norbert has to answer a number of clarification requests. Every answer must be a non-empty string, and no two answers may be identical.

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CF 102680D - One

The task is to classify each given natural number. A number is Prime if its only positive divisors are 1 and itself. It is Composite if it has at least one additional divisor. The special value 1 belongs to neither category because it has only one positive divisor.

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CF 102680B - Apple Pen

The problem describes an operation called "uh". If an item A is uh-ed with an item B, the result is a new item whose name is B-A, meaning the second item is placed before the first item with a hyphen between them.